• 3

Question:Size of aerial imagery from balloons and kites

Morgan is asking a question about balloon-mapping: Subscribe to answer questions on this topic

Morgan asked on January 05, 2017 17:32
2 | 3 answers | shortlink

Does anyone out there know how much area is covered by images that are taken from a balloon or kite? I know that the area will be different depending on high you are flying, but if anyone knows sizes at different altitudes, I would love to have that information.

I am planning a citizen science project in the Linville Gorge, NC to map the gorge's invasive species and target them for removal and treatment and I am trying to plan how many locations we will need to visit to map the whole gorge.

balloon-mapping kite-mapping citizen-science imagery

question:balloon-mapping question:kite-mapping


Log in to comment

3 Answers

The area of ground covered by an aerial photograph depends on both the height of the camera and the focal length of the lens. Lenses typically used for kite and balloon photography will cover a rectangular area with one dimension approximately equal to the height of the camera above the ground. So a Canon PowerShot with a focal length of 24mm (35mm equivalent) flown 300 feet high will capture a rectangle 300 feet by 450 feet. A Canon PowerShot with a focal length of 36mm (equiv) flown 300 feet high will capture a rectangle 200 feet by 300 feet. The PowerShot S100, S110, and S120 have an equivalent focal length of 24mm at the widest zoom. The PowerShot A495 has an equivalent focal length of 37mm at the widest zoom. Most point and shoot cameras are somewhere between these extremes.

A nice field of view calculator is here: http://www.scantips.com/lights/fieldofview.html#top


Chris's simplified answer is illustrated in our balloon mapping guide:


Most camera lenses have a viewing area angle close to 90 degrees, but often less, I.E. 70 degrees or so. Imagine your viewing area in two dimensions as an isosceles triangle with the camera's viewing angle as the top angle of the triangle, and your viewing area as the base.

Yes, thanks, Chris! I was focusing on finding the right image, not getting the right numbers in.

Sign up or Login to post an answer to this question.